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Breda 2014 / Holandsko, antuka , ATP Breda 2014 Tenis live
dotácia: 15 tis. USD
Jun 29, 2014
14:25
finále Kubler Jason (Aus.) [4] (273) 65.89% 2 6 6 6 I H2H O AI
Coppejans Kimmer (Bel.) [1] (206) 34.11% 1 3 7 3
Jun 28, 2014
19:20
semifinále Coppejans Kimmer (Bel.) [1] (206) 43.23% 2 7 6 I H2H O AI
Serra Florent (Fra.) (373) 56.77% 0 6 (4) 1
Jun 28, 2014
17:05
semifinále Kubler Jason (Aus.) [4] (273) 51.22% 2 6 3 7 I H2H O AI
De Loore Joris (Bel.) [8] (319) 48.78% 1 4 6 6 (6)
Jun 27, 2014
12:00
štvťfinále Kubler Jason (Aus.) [4] (273) 66.93% 2 6 6 I H2H O AI
Wang Tak-Khunn (Fra.) [5] (293) 33.07% 0 1 2
Jun 27, 2014
13:40
štvťfinále Coppejans Kimmer (Bel.) [1] (206) 61.76% 2 7 6 I H2H O AI
Monteiro Thiago (Braz.) [7] (368) 38.24% 0 6 (5) 4
Jun 27, 2014
17:55
štvťfinále Serra Florent (Fra.) (373) 55.03% 2 6 6 I H2H O AI
Westerhof Boy (Hol.) [3] (242) 44.97% 0 4 4
Jun 27, 2014
13:40
štvťfinále De Loore Joris (Bel.) [8] (319) 62.70% 2 6 6 I H2H O AI
Dischinger Eduardo (Braz.) (744) 37.30% 0 3 1
Jun 26, 2014
10:00
osemfinale Wang Tak-Khunn (Fra.) [5] (293) 58.99% 1 6 4 I H2H O AI
Meuffels Alban (Hol.) (788) 41.01% 0 4 2
Jun 26, 2014
18:40
osemfinale Westerhof Boy (Hol.) [3] (242) 48.61% 2 6 7 I H2H O AI
Fornell-Mestres Marc (Špan.) [Q] (991) 51.39% 0 3 5
Jun 26, 2014
15:20
osemfinale Serra Florent (Fra.) (373) 53.15% 2 6 6 I H2H O AI
Leite Wilson (Braz.) (372) 46.85% 0 0 2
Jun 26, 2014
10:00
osemfinale Kubler Jason (Aus.) [4] (273) 54.74% 2 6 6 I H2H O AI
Van Den Honert Vincent (Hol.) [Q] (1563) 45.26% 0 1 0
Jun 26, 2014
15:05
osemfinale De Loore Joris (Bel.) [8] (319) 45.76% 2 6 5 6 I H2H O AI
Ymer Elias (Švé.) (367) 54.24% 1 4 7 0
Jun 26, 2014
13:40
osemfinale Dischinger Eduardo (Braz.) (744) 49.73% 2 6 6 I H2H O AI
Arends Sander (Hol.) [Q] (1282) 50.27% 0 2 2
Jun 26, 2014
16:45
osemfinale Coppejans Kimmer (Bel.) [1] (206) 59.09% 2 7 6 I H2H O AI
Middelkoop Matwe (Hol.) (442) 40.91% 0 5 4
Jun 26, 2014
12:20
osemfinale Monteiro Thiago (Braz.) [7] (368) 39.36% 2 6 3 6 I H2H O AI
Aguilar Jorge (Chile) (515) 60.64% 1 4 6 0
Jun 25, 2014
13:05
1. kolo Fornell-Mestres Marc (Špan.) [Q] (991) 59.36% 2 6 7 I H2H O AI
De Vroome Max (Hol.) (1629) 40.64% 0 3 5
Jun 25, 2014
13:30
1. kolo Serra Florent (Fra.) (373) 50.83% I H2H O AI
van der Duim Antal (Hol.) [6] (276) 49.17%
Jun 25, 2014
10:00
1. kolo Meuffels Alban (Hol.) (788) 48.62% 2 6 6 I H2H O AI
Van De Zandschulp Botic (Hol.) [Q] 51.38% 0 1 2
Jun 25, 2014
11:40
1. kolo Van Den Honert Vincent (Hol.) [Q] (1563) 50.31% 2 7 6 I H2H O AI
Munoz-Abreu Jordi (Ven.) (812) 49.69% 0 6 (2) 4
Jun 25, 2014
10:00
1. kolo Kubler Jason (Aus.) [4] (273) 56.43% 2 6 6 I H2H O AI
Zednik Jan (ČR) [Q] (1675) 43.57% 0 1 2
Jun 25, 2014
17:00
1. kolo Middelkoop Matwe (Hol.) (442) 59.62% 2 6 6 I H2H O AI
Constantinovici Robert (Hol.) (1033) 40.38% 0 2 2
Jun 25, 2014
14:30
1. kolo Ymer Elias (Švé.) (367) 59.28% 2 6 6 I H2H O AI
Sporken Moos (Hol.) [Q] 40.72% 0 3 0
Jun 25, 2014
10:00
1. kolo Arends Sander (Hol.) [Q] (1282) 47.09% 2 1 7 6 I H2H O AI
Fortuna Claudio (Tal.) (397) 52.91% 1 6 6 (6) 3
Jun 24, 2014
10:00
1. kolo Aguilar Jorge (Chile) (515) 33.33% 2 6 3 6 I H2H O AI
Sant'Anna Bruno (Braz.) (416) 66.67% 1 4 6 3
Jun 24, 2014
10:00
1. kolo Monteiro Thiago (Braz.) [7] (368) 64.29% 2 6 7 I H2H O AI
Ouellette Greg (USA) (520) 35.71% 0 4 5
Jun 24, 2014
17:20
1. kolo Westerhof Boy (Hol.) [3] (242) 61.72% 2 6 6 I H2H O AI
Walendowsky Joao (Braz.) [Q] (1006) 38.28% 0 1 2
Jun 24, 2014
11:30
1. kolo Dischinger Eduardo (Braz.) (744) 45.71% 2 6 4 7 I H2H O AI
Hocevar Ricardo (Braz.) [2] (264) 54.29% 1 1 6 6 (7)
Jun 24, 2014
10:00
1. kolo Leite Wilson (Braz.) (372) 61.48% 2 6 3 6 I H2H O AI
Lootsma Niels (Hol.) (935) 38.52% 1 0 6 4
Jun 24, 2014
13:20
1. kolo Wang Tak-Khunn (Fra.) [5] (293) 62.20% 2 6 5 7 I H2H O AI
Griekspoor Scott (Hol.) (1162) 37.80% 1 3 7 6 (7)
Jun 24, 2014
10:00
1. kolo De Loore Joris (Bel.) [8] (319) 55.74% 2 6 6 I H2H O AI
Lindell Christian (Švé.) (394) 44.26% 0 2 3
Jun 24, 2014
00:00
1. kolo Serra Florent (Fra.) (373) 2 6 6 I H2H O AI
Kylar Kevin (Kan.) [LL] 0 1 2
Jun 24, 2014
13:00
1. kolo Coppejans Kimmer (Bel.) [1] (206) 58.96% 2 6 6 I H2H O AI
Bonapart Sebastiaan (Hol.) [Q] 41.04% 0 2 3
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